SSC Paper GEOMETRY Maharashtra Board

SSC Paper GEOMETRY Maharashtra Board

1. In the figure point Q is on the side MP such that MQ = 2 and MP = 5.5. Ray NQ is the bisector of  ∠MNP. Find MN:NP (2)

 

  

2. D is a point on side BC of ∆ABC such that ∠ADC = ∠BAC. Show that AC² = BC× DC. (3)

3. Find side of square whose diagonal is 16√2 cm (2)

4. In the figure ∠PQR = 90^o, T is the midpoint of side QR. Prove that : PR² = 4PT² – 3PQ²  (4)

5. Prove Pythagoras Theorem (4)

6. Two poles of height a meters and b meters are p metres apart. Prove that the height h of the point of intersection N of the lines joining the top of each pole to the foot of the opposite pole is ab

                           a+b